Agirl pulls her younger brother on a sled along a flat sidewalk (the total mass of the sled is 30kg). a frictional force of 50n opposes the pull. when moving, the girl pulls on the sled with a force of 150n at an angle of 30 degrees.

how much time will it take for the sled to travel 50?

what is the normal force?

6.13 s

219 N

Explanation:

Newton's law in the x direction:

∑F = ma

150 cos 30° N − 50 N = (30 kg) a

a = 2.66 m/s²

Δx = v₀ t + ½ at²

(50 m) = (0 m/s) t + ½ (2.66 m/s²) t²

t = 6.13 s

Newton's law in the y direction:

∑F = ma

Fn + 150 sin 30° N − (30 kg) (9.8 m/s²) = 0

Fn = 219 N

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