Apoint on a wheel of radius 40 cm that is rotating at a constant 5.0 revolutions per second is located 0.20 m from the axis of rotation. what is the acceleration of that point due to the spin of the wheel?

Explanation:

The centripetal acceleration of a point moving by circular motion is given by:

where

is the angular velocity

r is the distance from the axis of rotation

The point on the wheel makes 5.0 revolutions per second, so the frequency is

and the angular velocity is

While the distance of the point from the axis of rotation is

Substituting, we find the acceleration:

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

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