Three forces act on a moving object. one force has a magnitude of 76.5 n and is directed due north. another has a magnitude of 59.0 n and is directed due west. what must be the magnitude and direction of the third force, such that the object continues to move with a constant velocity?

F= 96.61 N

angle (θ) = 52.35°

Explanation:

given,

One Force F₁ = 76.5 N

second force F₂ = 59 N

That means F₃ must equal –(F₁+F₂) so the net sum of the three is zero.

F₁+F₂,  since they are orthogonal, is easy.

F₁+F₂ =

   =

   = 96.61 N

Force is acting of magnitude F= 96.61 N

angle (θ) = 52.35°

2b2t

explanation:

2b2t