A0.250 kg block on a vertical spring with spring constant of 4.45 ✕ 103 n/m is pushed downward, compressing the spring 0.080 m. when released, the block leaves the spring and travels upward vertically. how high does it rise above the point of release?

h=5.81 m

Explanation:

Given

Mass of block(m)=0.250 kg

Spring Constant

Initial elongation =0.080 m=8 cm

Thus Initial Potential Energy stored =Final Potential Energy stored in Block

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .

i think its d if wrong im sorry