Acannonball is catapulted toward a castle. the cannonball’s velocity when it leaves the catapult is 51.6 m/s at an angle of 37.0° with respect to the horizontal, and the cannonball is 7.00 m above the ground at this time. the y-axis points up. what is the y-component of the cannonball’s velocity just before it lands?

Explanation:

From the exercise we know the cannonball's initial velocity, the angle which its released with respect to the horizontal and its initial height

If we want to know whats the y-component of velocity we need to use the following formula:

Knowing that

So, the cannonball's y-component of velocity is

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

answer: good job it's all correct !

explanation: