430500/66300a satellite in a circular orbit 1250 kilometers above earth makes one complete revolution every 190 minutes. what is its linear speed? assume that earth is a sphere of radius 6400 kilometers. (round your answer to two decimal places.)

4216,22 m/s

Explanation:

Linear speed can be calculated with:

V = 2πr / T

Where  V is linear speed, r is radius of the circular path which the object takes and T is period of the rotational motion. We want to calculate the speed in SI units, so:

1250 kilometers = 1250  *  meters

6400 kilometers = 6400 * meters

We will take r as the sum of radius of the Earth and height of the satellite because we need the distance between object and its centre of rotation. (Figure 1).  

r= 1250 *  + 6400 *   = 7650 *   meters

T=190 minutes * 60 = 11400 seconds.  

We will take pi as   3.1415, let us place values to the equation:

V= 4216,22  m/s

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle