The diagram below represents a horizontal force of 20 newtons applied to a 5.0 kilogram box to push it and
rough, horizontal floor at a constant velocity of 3.0 m/s to the right.
3.0 m/s
20 n
5.0 kg
b. determine the magnitude of the force of friction acting on the box. explain your answer.

20 N

Explanation:

There are two forces acting on the box:

- The force of push, F, forward, of magnitude F = 20 N

- The force of friction, , backward

So, the equation of motion for the box is

where

m = 5.0 kg is the mass of the box

a is its acceleration

The box is sliding at constant velocity: this means that its acceleration is zero

a = 0

So, the equation becomes

Therefore, we can find the magnitude of the force of friction:

. west

number of electrons for neutral cl