A120kg defensive lineman tackles a stationary quarterback at 6.5 m/s it takes .25 seconds for the lineman to completely stop what is the magnitude of force exerted on the lineman during the collision

F = -3120 N

Explanation:

Lets write out everything we have:

Lineman:

m = 120kg

V1 = 6.5m/s

v2 = 0

t = 0.25

We should find acceleration, to move on to the next step;

a = v2-v1 / t

a = 0 - 6.5 / 0.25

a = -26m/s^2

Now we can use the Fnet formula and solve for F;

Fnet  = ma

fnet = (120)(-26)

F = -3120 N

the answer is a)

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