Block b has mass 4.00 kg and sits at rest on a horizontal, frictionless surface. block a has mass 2.00 kg and sits at rest on top of block b. the coefficient of static friction between the two blocks is 0.400. a horizontal force p⃗ is then applied to block a.
what is the largest value p can have and the blocks move together with equal accelerations?

P= 12 N

Explanation:

Given that

Mass of B block m= 4 kg

Mass of A block m'= 2 kg

μ = 0.4

Given that block B is on friction less surface .If these blocks moves together with same acceleration only if the this acceleration will be equal to the acceleration of block B which produce by friction force.

Lets take acceleration is a m/s²

For block A

fr= μ m' g

fr= 0.4 x 2 x 10 N

fr= 8 N    

For block B

fr= m a

8 = 4 .a

a = 2 m/s²

If they moves together

P= (m+m') a

P = (4+ 2) x 2

P = 12 N

P= 12 N

learn it on the intertant so you can solve

its lower due to the doppler effect.: apex