Find the work w1 done on the bltwo tugboats pull a disabled supertanker. each tug exerts a constant force of 2.10×106 n , one at an angle 10.0 ∘ west of north, and the other at an angle 10.0 ∘ east of north, as they pull the tanker a distance 0.890 km toward the north. ock by the force of magnitude f1 = 80.0 n as the block moves from xi = -5.00 cm to xf = 6.00 cm .

The work done is .

Explanation:

Given that,

Force

Angle = 10.0°

Distance = 0.890 km

Magnitude of force = 80.0 N

Initial distance = -5.00 cm

Final distance = 6.00 cm

According to figure,

The horizontal forces are same in magnitude and opposite direction.

So, neglect these two forces.

we can take only vertical components of the force.

We need to calculate the total force

.....(I)

We need to calculate the work done

Using formula of work done

Put the value into the formula

Hence, The work done is .

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explanation:

my daughter rae

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.