If a high jumper needs to make his center of gravity rise 1.50 m, how fast must he be able to sprint? assume all of his kinetic energy can be transformed into potential energy. for an extended object, the gravitational potential energy is u = mgh, where h is the height of the center of gravity.

v = 5.42 m/s

Explanation:

given,

height of the jumper = 1.5 m

velocity of sprinter = ?

kinetic energy can be transformed into potential energy

v = 5.42 m/s

Speed of the sprinter is equal to v = 5.42 m/s

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

there are no contact forces mentioned on the list of choices that you've provided.