If you visited mount shasta city (elevation 900 m [3000 ft.]) and found the outside air temperature to be 27°c (81°f), what would be the air temperature at the summit of mount shasta (elevation 4200 m [14,000 ft.]) at that moment-assuming that the temperature conditions with altitude change at an average, or normal, lapse rate?

5.9°C  

Explanation:

Summit height = 4200 m = 4.2 km

Ground height = 900 m = 0.9 km

Height above the ground = 4.2 km - 0.9 km = 3.3 km

the average or normal lapse rate is expected to be 6.4°C/km.

 the temperature at summit of mountain would be =

= Temperature at ground - [(4.2 km - 0.9 km) × lapse rate]

= 27° - [ 3.3 × 6.4° ]

= 27° - 21.12 °

= 5.88°C

≈ 5.9°C  

Hence, the air temperature at the summit is 5.9°C  

they start with the same

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so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards