Along jumper goes into a jump at an angle of 20.0° above the horizontal and at a speed of 9.9 m/s. what is his time of flight (the time the jumper is in the air), in units of seconds?

T = 0.69 s

Explanation:

given,

speed of the long jumper = 9.9 m/s

angle of the jump = 20°

time of flight calculation = ?                            

using equation of time of flight

T = 0.69 s                                                      

so, the time of flight of the jumper is equal to T = 0.69 s

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