A2.1 kg ball is attached to a ceiling by a string. the distance from the ceiling to the center of the ball is 1.10 m, and the height of the room is 3.00 m. (a) what is the gravitational potential energy associated with the ball relative to the ceiling? j (b) what is the gravitational potential energy associated with the ball relative to the floor? j (c) what is the gravitational potential energy associated with the ball relative to a point at the same elevation as the ball? j

Explanation:

Given

mass of ball =2.1 kg

height of room =3 m

Length of string=1.1 m

Gravitational Potential Energy of ball relative to the ceiling

=mgh

where h is distance between ceiling and ball

=-22.638 J

negative indicates ball is below the reference Plane

(b)Gravitational Potential Energy of ball relative to the Floor

=mgh

here h=3-1.1=1.9 m

(c)Gravitational Potential Energy of ball relative to a point at the same elevation as the ball

=mgh

here h=0 as it is in the same plane as of ball

=0

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

the inner core.

good luck: )

klicker