In a control system, an accelerometer consists of a 4.70-g object sliding on a calibrated horizontal rail. a low-mass spring attaches the object to a flange at one end of the rail. grease on the rail makes static friction negligible, but rapidly damps out vibrations of the sliding object. when subject to a steady acceleration of 0.800g, the object should be at a location 0.500 cm away from its equilibrium position. find the force constant of the spring required for the calibration to be correct.

7.37 N/m

Explanation:

Given:

Mass of the object = 4.70 g = 0.0047 kg

acceleration = 0.800 g = 0.800 × 9.81 = 7.848 m/s²

Displacement = 0.500 cm = 0.005 m

Now,

Force by the object = Mass × Acceleration

= 0.0047 × 7.848

= 0.0368856 N

and,

Force by the spring = kx

where, x is the displacement

k is the spring constant

thus,

0.0368856 = k × 0.005

or

k = 7.37 N/m

a high pressure system is a dense air mass that is usually cooler and drier than the surrounding air. a low pressure system is a less dense air mass that is usually wetter and warmer than the surrounding air.

in general, areas that experience high atmospheric pressure also experience fair weather. low pressure systems can cause the formation of clouds and storms. air usually flows from areas of high pressure to areas of low pressure..

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge