Suppose that you want to move a heavy box with mass 30.0 kg across a carpeted floor. you try pushing hard on one of the edges, but the box does not move. suppose that you are pushing against the box from an angle 30.0∘ above horizontal with a force of magnitude 240 n. what is the magnitude of the friction force acting on the box?

             f =  207.85 N

Explanation:

given,

mass of box = 30 kg

angle made with the horizontal = 30.0∘

Horizontal force = 240 N

now calculating normal force

N = F_y + mg

N = F sin θ+ mg

N = 240 sin 30.0∘ + 30 × 9.8

N = 414 N

Now

frictional force = F _x

             f = F cos θ

             f = 240 × cos 30.0∘

             f =  207.85 N

frictional force acting on the box is 207.85 N