An alaskan rescue plane traveling 45 m/sdrops a package of emergency rations froma height of 145 m to a stranded party of reese (enr647) – homework 3, 2d motion 19-20 – dowd – (mcdanielmphy119203)3explorers. the acceleration of gravity is 9.8 m/s2.where does the package strike the groundrelative to the point directly below where it

package will strike at a distance of 244.7  m

Explanation:

Given data;

Velocity of plane 45 m/s

Acceleration due to gravity 9.8 m/s^2

horizontal component of plane velocity is ux = 45 m/s

vertical component is zero

in the same way

ay = - 9.8  m/s^2

ax = .0 m/s^2

motion in y direction = -145 m

from equation of motion time of flight is

solving for t  we get

t = 5.439 sec

Motion in x direction

s = 244.79 m

Therefore package will strike at a distance of 244.7  m

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