A2.29-kg cart on a long, level, low-friction track is heading for a small electric fan at 0.21 m/s . the fan, which was initially off, is turned on. as the fan speeds up, the magnitude of the force it exerts on the cart is given by at2, where a = 0.0200 n/s2.

The speed of the cart at time 3.5 sec is 0.37 m/s.

Explanation:

Given that,

Mass = 2.29 kg

Speed = 0.21 m/s

Force = at²

a = 0.0200 N/s²

Suppose we find the speed of the cart at 3.5 sec after the fun is turn on

We need to calculate the acceleration

Using newton's law

The speed of the cart at time 3.5 sec is

Using equation of motion

Put the value into the formula

Hence, The speed of the cart at time 3.5 sec is 0.37 m/s.