43. a rocket sled accelerates at a rate of 49.0m/s2. its passenger has a mass of 75.0 kg. (a) calculate the horizontal component of the force the seat exerts against his body. compare this with his weight using a ratio. (b) calculate the direction and magnitude of the total force the seat exerts against his body.

(a) 3675 N

Assuming that the acceleration of the rocket is in the horizontal direction, we can use Newton's second law to solve this part:

where

is the horizontal component of the force

m is the mass of the passenger

is the horizontal component of the acceleration

Here we have

m = 75.0 kg

Substituting,

(b) 3748 N, 11.3 degrees above horizontal

In this part, we also have to take into account the forces acting along the vertical direction. In fact, the seat exerts a reaction force (R) which is equal in magnitude and opposite in direction to the weight of the passenger:

where we used

as acceleration of gravity.

So, this is the vertical component of the force exerted by the seat on the passenger:

and therefore the magnitude of the net force is

And the direction is given by

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.