a runner begins from rest and accelerates at a rate of 0.22 meters per second' for 15
seconds. calculate the distance traveled by the runner while he accelerates.
car

25 m

Explanation:

Given:

v₀ = 0 m/s

a = 0.22 m/s²

t = 15 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (15 s) + ½ (0.22 m/s²) (15 s)²

Δx = 24.75 m

Rounded to two significant figures, the runner moves a distance of 25 m.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

the higher the current the higher the mag field around it the higher the influence on the compass