Acliff diver positions herself on a cliff that angles downwards towards the edge. the length of the top of the cliff is 45.0 m and the angle of the cliff is θ = 21.0° below the horizontal. the cliff diver runs towards the edge of the cliff with a constant speed, and she reaches the edge of the cliff in a time of 6.10 s. after running straight off the edge of the cliff (without jumping up), the diver falls h = 20.0 m before hitting the water.
after leaving the edge of the cliff how much time does the diver take to get to the water? how far horizontally does the diver travel from the cliff face before hitting the water? remember that the angle is at a downward slope to the right.

Ithink the answer would be a

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.