Units for "g" the gravitational constant.

in just about every source, i see that the value for "g" is
6.67 * 10^-11 m³ * kg^-1 * s^-2

is this the same as stating that g=
6.67 * 10^-11 m³ / (kg * s²) ?

Yes, both of them are correct.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )