A2.98 nf parallel-plate capacitor is charged to an initial potential difference of 49 v and then isolated. the dielectric material between the plates has a dielectric constant of 3.1. what is the potential difference of the capacitor after the dielectric is withdrawn? answer in units of v.

151.9 V

Explanation:

Given

Capacitance (C)=2.98 nF

Potential difference=49 V

dielectric strength k=3.1

Charge remains same after the removal of dielectric

thus

Now dielectric is removed so capacitance decreases to

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27

the answer is a. hope this .