Awet bar of soap slides down a ramp 9.2 m long inclined at 8.0∘ .

how long does it take to reach the bottom? assume μk = 0.056.
express your answer to two significant figures and include the appropriate units.

The time taken by the bar to reach the bottom t=4.886s

Given:

Displacement of the bar S=9.2m

Angle of inclination

Coefficient of friction factor

To find:

How long it takes to reach the bottom ‘t’

Step by Step Explanation:

Solution:

We know that the formula for weight of the soap bar is given as

The frictional force acting on this soap bar is determined by

To determine the constant acceleration of the bar, we derive as

Here and thus

Where=Force imparted due to weight

=Frictional Force

m=Mass of the bar

g=Acceleration due to gravity

a=Acceleration of the bar

and are the angles involved in the system

If the bar starts from the rest

Equations of motion involved in calculating the displacement of the bar is given as

, From this

Where s= displacement or length moved by the bar

a=Acceleration of the bar

t=Time taken to reach bottom

Substitute all the known values in the above equation we get

and we know that

t=4.886s

Result:

Thus the time taken by the bar to reach the bottom is t=4.886s

when the velocity of a mass on a spring is zero, the acceleration is at a maximum .