Compute your average velocity in the following two cases: (a) you walk 73.2m at a speed of 1.22m/s and then run 7302m at a soeed of 3.05 m/s along a stright track. (b) you walk for 1.00min at a speed of 1.22m/s and then run for 1.00 at 3.05m/s along a stright track. (c) graph x verses t for both cases and indicate how the average velocity is found on the graph

a) 3.00 m/s, approximately and b) 2.135 m/s

Explanation:

a) x1 = 73.2 m and v1 = 1.22 m/s, then

;

x2 = 7302 m and v2 = 3.05 m/s, then

.

So the average speed is

.

b) t1 = 60 s and v1 = 1.22 m/s, then

;

t2 = 60 s and v2 = 3.05 m/s, then

;

So the average speed is

.

c) Plot cumulative distance Vs. cumulative time, the slope of the line going through the origen and the final coordinate, is the velocity

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//