To win the game, a place kicker must kick a
football from a point 19 m (20.7784 yd) from
the goal, and the ball must clear the crossbar,
which is 3.05 m high. when kicked, the ball
leaves the ground with a speed of 15 m/s at
an angle of 51.7
◦
from the horizontal.
the acceleration of gravity is 9.8 m/s
2
.
by how much vertical distance does the ball
clear the crossbar?
answer in units of m.

0.57 m

Explanation:

First of all, we need to calculate the time it takes for the ball to cover the horizontal distance between the starting position and the crossbar. This can be done by analzying the horizontal motion only. In fact, the horizontal velocity is constant and it is

And the distance to cover is

d = 19 m

So the time taken is

Now we want to find how high the ball is at that time. The initial vertical velocity is

So the vertical position of the ball at time t is

where g = 9.8 m/s^2 is the acceleration of gravity. Substituting t = 2.04 s, we find

The crossbar height is 3.05 m, so the difference is

So the ball passes 0.57 m above the crossbar.

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

mass and volume are the answers you are looking for