Physics, 11.10.2019 03:30 leeshaaa17

Which of the following statements is(are) true?

(a) the total mechanical energy of a system, at any one instant, is either all kinetic or all potential energy.
(b) the total mechanical energy of a system is constant only if nondissipative interactions occur.
(c) the total mechanical energy of a system is constant only if dissipative interactions occur.
(d) the total mechanical energy of a system is equally divided between kinetic and potential energy.
(e) mechanical energy can be dissipated to nonmechanical forms of energy.

Answers: 3

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Answer from: Squara

B) True

E)True

Explanation:

As we know that the total mechanical energy is summation of potential energy and kinetic energy.

A)False

This statement is false because it say that all kinetic or all potential energy.This should not be all.

B) True

When dissipative interactions occurs then the total mechanical energy of the system can not be constant.But if nondissipative interactions occur then the total mechanical energy of the system is remain constant.

C)False

D)False

This is not true because we know that total mechanical energy is summation of potential energy and kinetic energy.But does not tell that it will be equally divided between kinetic and potential energy.

E)True

Yes it is true because the mechanical energy can be converted in to heat energy due to friction force.

Answer from: Quest

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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