Aperson throws a ball straight up into the air with a speed of 7.3m/s. how high does the ball go?

2.6645m

Explanation:

applying motion equations we can find the answer,

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

s =  distance traveled

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g =10 m/s2 downwards)

that is,

gets less

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y