Physics, 10.10.2019 16:10 joeylozier15

Acar of mass 1100 kg that is traveling at 27 m/s starts to slow down and comes to a complete stop in 578 m. what is the magnitude of the average braking force acting on the car?

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Answer from: isabelj2004

A car of mass 1100 kg that is traveling at 27 m/s starts to slow down and comes to a complete stop in 578 m, experiences an average braking force of -6.9 × 10² N.

A car is initially moving at 27 m/s (u). After a displacement of 578 m (s) it stops, that is, its final velocity (v) is zero. We can calculate the acceleration (a) of the braking force using the following kinematic equation.

$v^{2} = u^{2} + 2 \times a \times s\\\\a = \frac{v^{2} - u^{2}}{2 \times s} = \frac{(0m/s)^{2} - (27m/s)^{2}}{2 \times 578m} = -0.63 m/s^{2}$

The car of mass (m) 1100 kg experiences an acceleration of -0.63 m/s². We can calculate the associated force (F) using Newton's second law of motion.

$F = m \times a = 1100 kg \times (-0.63 m/s^{2} ) = -6.9 \times 10^{2} N$

A car of mass 1100 kg that is traveling at 27 m/s starts to slow down and comes to a complete stop in 578 m, experiences an average braking force of -6.9 × 10² N.

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Answer from: lily3934

A car of mass 1100 kg that is travelling at 27 m/s starts to slow down and comes to a complete stop in 578 m. The magnitude of the average braking force acting on the car is 693 N.

Explanation:

The given car of mass of 1100 kg has been travelling at a speed of 27 m/s and the breaking force was applied. To determine the breaking force, following steps can be undertaken,

Applying the equations of motion, as we know,

$v^{2}=u^{2}-2 a s$

As the car comes to rest, final velocity v=0. Substituting the known value into the third equation of motion as mentioned above, we get,

$0=(27 \times 27)-(2 a \times 578)$

$2 a \times 578=27 \times 27$

Then, Deacceleration is

$a=\frac{27 \times 27}{2 \times 578}=\frac{729}{1156}=0.63 \mathrm{m} / \mathrm{s}^{2}$

Now to calculate the force,

$F=m a=1100 \times 0.63=693 \mathrm{N}$

Answer from: Quest

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2 y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x | y

-2 | 2

0 | 8

2 | 14

Create a table of x and y values for the expression y/4=3/4x+2. use the x values of -2,0, and 2. i n

Answer from: Quest

the answer is 3.1 his answer is wrong mines is right

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