Aphysics professor did dare- devil stunts in his spare time. his last stunt was an attempt to jump across a river on a motorcycle (fig. p3.63). the takeoff ramp was inclined at 53.0°, the river was 40.0 m wide, and the far bank was 15.0 m lower than the top of the ramp. the river itself was 100 m below the ramp. ignore air resistance.
(a) what should his speed have been at the top of the ramp to have just made it to the edge of the far bank?
(b) if his speed was only half the value found in part (a), where did he land?

a) 17.8 m/s

b)28.3 m

Explanation:

Given:

angle A = 53.0°, sinA = 0.8, cosA = 0.6

d = 40.0 m, h = 15.0 m, H = 100 m,

(a) find speed v

vertical displacement -h = v×sinA×t - 0.5gt^2

-15 = 0.8vt - 4.9t^2 (1)

horizontal displacement d = v×cosA×t = 0.6×v×t

so v×t = d/0.6 = 40/0.6

plug it into (1) and get

-15 = 0.8*40/0.6 - 4.9t^2

t = 3.734 s

v = (40/0.6)/t = 17.8 m/s

(b) If his speed was only half the value found in (a), where did he land?

v = 17.8/2 = 8.9 m/s

vertical displacement = -H = v×sinA×t - gt^2/2

4.9×t^2 - 8.9×0.8×t - 100 = 0

t = 5.30 s

d = v×cosA×t = 28.3 m

the answer would be a

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.