Acar traveling at 22 m/s comes to an abrupt halt in 0.1 second when it hits a tree. what is the deceleration of the car.

The deceleration of the car is -220 m/s²

Explanation:

Hi there!

The equation for the velocity of an accelerated object moving along a straight line is as follows:

v = v0 + a · t

Where:

v = velocity at time "t"

v0 = initial velocity

a = acceleration

t = time

When the car stops, its velocity is 0. Then, using the equation of velocity we can calculate the acceleration of the car since we know the initial velocity and the time after which the car comes to stop:

v = v0 + a · t

0 = 22 m/s + a · 0.1 s

-22 m/s / 0.1 s = a

a = -220 m/s²

The deceleration of the car is -220 m/s²

Have a nice day!

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation