Abaseball is thrown horizontally from a height of 9.60 m above the ground with a speed of 30.0 m/s. where is the ball after 1.40 s have clapsed?

The baseball will be  42 meters horizontally from where it was thrown and at the heigth of the ground.

Explanation:

this is a problem that involves basic mechanics in two directions, for the x axis we have a constant speed problem and for the y axis we have a constant aceleration problem, using the equations for each one of these we got:

where Xo and Yo are the inital position for x and y axis, in this case and , Vox and Voy are the initial speed for x and y axis, in this case and since the ball was throwns horizontally, and a is the acceleration in the y axis which is the gravitational aceleration, that means (the minus sign is because the gravitational aceleration is towards the negative y axis).

Replacing these values we have to equations that will help us find the position of the ball at any time we want:

and here we just have to replace the time value and solve, so:

and that's it, the ball is 42 meters horizontally from where it was throwns and at the heigth of the ground.

your answer is, orbit around the nucleus

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.