Aprojectile thrown from the ground reached a horizontal displacement of 50 [m] and a maximum height of 100 [m]. what are the magnitude of the initial velocity v0 and the launching angle θ (withrespect to the horizontal) of the projectile? use g = 9.81 m/s^2

u = 44.44 m/s

Explanation:

given,

horizontal displacement = 50 m

maximum height = 100 m

initial velocity (v₀) = ?

launching angle(θ) = ?

using formula

........(1)

.........(2)

dividing equation (2)/(1)

now using equation (2)

u = 44.44 m/s

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.