A5.20 kg bucket of water is accelerated upward by a cord of negligible mass whose breaking strength is 70.0 n. if the bucket starts from rest, what is the minimum time required to raise the bucket a vertical distance of 14.0 m without breaking the cord?

Time, t = 2.76 seconds  

Explanation:

It is given that,

Mass of the bucket, m = 5.2 kg

The breaking strength of the cord, T = 70 N

Initially, the bucket is at rest, u = 0

Bucket is to raise a distance of 14 meters, d = 14 m

At equilibrium, the net force acting on the bucket is given by :

When the bucket is moving in upward direction,

a is the acceleration of the bucket.

Let t is the minimum time required to raise the bucket a vertical distance of 14.0 m without breaking the cord. Using second equation of motion as :

t = 2.76 seconds

So, the minimum time required to raise the bucket a vertical distance is 2.76 seconds. hence, this is the required solution.

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

object 2 because all the other ones are wrong