Astick of length 6.2 cm has charged globes on either end, one charged to 16 μc, while the other one is charged to 1μc. the rod is placed perpendicular to a 1174 n/c field. what is the force on the stick?
what is the polarization of the bar?
how much torque does it feel?

Net force = 0.0191 N

T=0.00054 N.m

p=99.2 μC.cm

Explanation:

Given that

L= 6.2 cm

q₁= 16μC

q₂=1μC

E= 1174 N/C

We know that

F = q E

F₁ = q₁ E

F₁ = 0.018 N

F₂=q₂ E

F₂=0.0011 N

Net force = F₁+F₂

Net force = 0.0191 N

Torque ,T

T = (F₁-F₂) L/2

T = (0.018 - 0.0011 ) x 0.032

T=0.00054 N.m

Polarization ,p

p= q d

p= 16 x 6.2 μC.cm

p=99.2 μC.cm

i believe the answer is a hope it and is correct

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