During a storm, a tree limb breaks off and comes to rest across a barbed wire fence at a point that is not in the middle between two fence posts. the limb exerts a downward force of 176 n on the wire. the left section of the wire makes an angle of 12.5° relative to the horizontal and sustains a tension of 413 n. find the (a) magnitude and (b) direction (as an angle relative to horizontal) of the tension that the right section of the wire sustains.

Magnitude - 11.83 Degree

Direction - 422.42 N

Explanation:

Given data:

Downward force on wire 176 N

Angle made by left section of wire 12.5 degree with horizontal

Tension force = 413 N

From figure

Applying quilibrium principle at point A

The vertical and horizontal force is 0

then we have

  ........1

    .......2

.......3

divide equation 3 by 1

we get

 ...........4

from equation 3 and 4

T = 422.42 N

no. dot product   =0 when vecs at right angles

it is a negative acceleration