A100.0 ml sample of 1.020 m hcl is mixed with a 50.0 ml sample of 2.040 m naoh in a styrofoam cup. if both solutions were initially at 24.53°c, and the enthalpy of the neutralization reaction is −57 kj/mole of h2o formed, what is the final temperature of the mixture? assume that the solution has a density of 1.00 g/ml and a specific heat of 4.184 j/g°c, and that the styrofoam cup has an insignificant heat capacity.

Explanation:

Given data:

0.1 L HCl × 1.020 mol/L = 0.102 mol HCL

0.05 L NaOH × 2.040 mol/L = 0.102 mol NaOH

NaOH + HCl \rightarrow  H_2O + NaCl

0.102 mol HCl /1 mol HCl × 1 mol H2O = 0.102 mol H2O

0.102 mol H2O / 1 mol H2O × 57000 J = 5814 J

M(t)=150*1=150 g

we know that heat energy is given as

where c is specific heat

total energy released is = 57 \times 0.102 = 5.814 kJ

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.