Astudent wishes to determine the heat capacity of a coffee-cup calorimeter. after she mixes 94.8 g of water at 60.4°c with 94.8 g of water, already in the calorimeter, at 22.3°c, the final temperature of the water is 35.0°c. calculate the heat capacity of the calorimeter in j/k. use 4.184 j/g°c as the specific heat of water. enter to 1 decimal place.

JC⁻¹

Explanation:

= mass of water added to calorimeter = 94.8 g

= initial temperature of the water added = 60.4 C

= specific heat of water = 4.184 Jg⁻¹C⁻¹

= mass of water available to calorimeter = 94.8 g

= initial temperature of the water in calorimeter = 22.3 C

= final equilibrium temperature = 35 C

= Heat gained by calorimeter

Using conservation of heat

Heat gained by calorimeter = Heat lost by water added - heat gained by water in calorimeter

J

= Change in temperature of calorimeter

Change in temperature of calorimeter is given as

C

Heat capacity of calorimeter is given as

JC⁻¹

c. magnitude and direction

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