Astudent uses a spring to launch a marble vertically in the air. the mass of the marble is 0.002 kg and
when the spring is stretched 0,05 m it exerts a force of 10 n. what is the maximum height the marde can
reach?

25 m

Explanation:

Work to compress spring = gravitational potential energy of marble

W = PE

Fd = mgh

h = Fd / (mg)

Given F = 10 N, d = 0.05 m, m = 0.002 kg, and g = 10 m/s²:

h = (10 N) (0.05 m) / (0.002 kg × 10 m/s²)

h = 25 m

25 m

Explanation:

A student uses a spring to launch a marble vertically in the air. The mass of the marble is 0.002 kg and  when the spring is stretched 0,05 m it exerts a force of 10 N. Therefore, the maximum height the marde can  reach is 25 m.

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

i would say