When a base jumper leaps from a tall cliff, the distance she falls (in meters) after t seconds, accounting for air resistance, is gien by d(t)equals=startfraction m over k endfraction ln [hyperbolic cosine (startroot startfraction kg over m endfraction endroot t )]m klncosh kg mt, where m is her mass in kilograms, gequals=9.8 m divided by s squared9.8 m/s2 is the acceleration due to gravity, and k is a physical constant. her velocity t secondst seconds after jumping is v(t)equals=d prime (t )d′(t)equals=startroot startfraction mg over k endfraction endroot hyperbolic tangent (startroot startfraction kg over m endfraction endroot t )mg ktanh kg mt. complete parts (a) through (d) below. a. compute the jumper's terminal velocity, which is defined as modifyingbelow lim with t right arrow infinitylimt→[infinity]v(t).
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Physics, 22.06.2019 11:20
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Physics, 22.06.2019 21:00
Ascientist wants to test ways to reduce pollution in lake . what is the bestway of doing this
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When a base jumper leaps from a tall cliff, the distance she falls (in meters) after t seconds, acco...
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