A580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used as a filament in an incandescent light bulb. when the light bulb is connected to a battery, a current of 0.526 a is measured through the filament. (note: tungsten has a resistivity of 4.9 × 10-8 ω • how many electrons pass through this filament in 5 seconds?

1.64 *10^19 electrons

Explanation: In order to the explain this problem we have to consider the following:

The current= charge/time; so

as the electrons move in the tungsten wire we have:

0.526 C/s= N electrons per second* charge of electron=

N electrons/s= 0.526/1.6*10^-19= 3.28 *10^18 electrons/s

Then, during  5 seconds  will pass:

3.28 *10^18 electrons/s*5 5s= 1.64 *10^19 electrons

see earlier

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