Physics, 05.10.2019 05:10 goalltheway4768

The velocity of the wind relative to the water is crucial to sailboats. suppose a sailboat is in an ocean current that has a velocity of 1.86 m/s in a direction 25.1° east of north relative to the earth. it encounters a wind that has a velocity of 4.13 m/s in a direction of 52.7° south of west relative to the earth. what is the velocity of the wind relative to the water? (enter the magnitude in m/s and the direction in degrees south of west.)

Answers: 2

Show answers

Answers

Answer from: dooboose15

$v_{wE}=2.334m/s$

$\alpha_{wE}=44.81^\circ$

Explanation:

The velocity of the wind relative to the Earth is the sum of the velocity of the wind relative to the sailboat and the velocity of the sailboat relative to the Earth, $v_{wE}=v_{ws}+v_{sE}$ , as vectors. We always need to separate into components, and as usual we will take East as the positive x direction, North as the positive y direction, and the angles $\theta$ measured from the East direction and anticlockwise.

The velocity of the sailboat relative to the Earth $v_{sE}$ is the velocity of the ocean current:

$v_{sEx}=v_{sE}cos(\theta_{sE})=(1.86m/s)cos(90^\circ-25.1^\circ)=0.789m/s$

$v_{sEy}=v_{sE}sin(\theta_{sE})=(1.86m/s)cos(90^\circ-25.1^\circ)=1.684m/s$

We do the same for the velocity of the wind relative to the sailboat $v_{ws}$ :

$v_{wsx}=v_{ws}cos(\theta_{ws})=(4.13m/s)cos(180^\circ+53.7^\circ)=-2.445m/s$

$v_{wsy}=v_{ws}sin(\theta_{ws})=(4.13m/s)cos(180^\circ+53.7^\circ)=-3.329m/s$

And finally use the original formula for each direction:

$v_{wEx}=v_{wsx}+v_{sEx}=0.789m/s-2.445m/s=-1.656m/s$

$v_{wEy}=v_{wsy}+v_{sEy}=1.684m/s-3.329m/s=-1.645m/s$

With the components we can easily calculate the magnitude of the velocity vector:

$v_{wE}=\sqrt{v_{wEx}^2+v_{wEy}^2}=2.334m/s$

For the angle, we must notice that the components are negative, so by taking $v_{wEy}$ as the opposite cathetus and $v_{wEx}$ as the adjacent one we will have our angle in degrees south of west (which for avoiding confusion with the previous convention I'll call $\alpha_{wE}$ ):

$\alpha_{wE}=Arctg (\frac{v_{wEy}}{v_{wEx}})=44.81^\circ$

Answer from: Quest

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

Answer from: Quest

i already answered it by 34/s

Another question on Physics

Physics, 22.06.2019 01:10

If vx = 7.00 units and vy = -7.60 units, determine the magnitude of v⃗ . determine the direction of v⃗ .

Answers: 2

Answer

Physics, 22.06.2019 03:30

Will give brainliest! jay rides his 2.0-kg skateboard. he is moving at speed 5.8 m/s when he pushes off the board and continues to move forward in the air at 5.4 m/s. the board now goes forward at 13 m/s.a. determine jay’s mass.b. determine the change in the internal energy of the system during this process.(express your answer to two significant figures and include the appropriate units.)

Answers: 1

Answer

Physics, 22.06.2019 03:30

What is the momentum of a 2 kg object moving at 15 meters per second

Answers: 1

Answer

Physics, 22.06.2019 11:50

The scalar triple product computes the magnitude m of the moment of a force vector f about a specified line. it is m = (r × f) · n, where r is the position vector from the line to the point of application of the force and n is a unit vector in the direction of the line. use matlab to compute the magnitude m for the case where f = [12, −5, 4] n, r = [−3, 5, 2] m, and n = [6, 5, −7].

Answers: 3

Answer

You know the right answer?

The velocity of the wind relative to the water is crucial to sailboats. suppose a sailboat is in an...

Questions