How would the composition of an atom change if both the atomic number and mass number each increase by one ?

The atom gains one proton

Explanation:

Basic definitions:

- The atomic number of an atom is the number of protons in the nucleus:

Z = p

where p is the number of protons

- The mass number of an atom is the number of protons + neutrons in the nucleus:

A = p + n

where p is the number of protons and n the number of neutrons

In this problem, both the atomic number and the mass number increases by one unit, so:

Z' = Z + 1

A' = A + 1

Re-writing the two equations in terms of p and n:

p' = p + 1 (1)

p' + n' = (p+n) + 1 (2)

From eq.(1), we see that the number of protons has increased by one unit. Substituting p' from eq.(1) into eq.(2),

(p+1) + n' = (p+n) + 1

p + 1 + n' = p + n +1

--> n' = n

which means that the number of neutrons has not changed.

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.