Aball rolls over the edge of a table with a horizontal velocity v m/s. the height of the table is 1.6 m and the horizontal range of the ball from the base of the table is 20 m. how long does it take for the ball to hit the ground?

The time taken to hit the ground by the ball is required.

The time taken to hit the ground is 0.57 s.

v = Horizontal velocity

y = Height of table = 1.6 m

x = Displacement in x direction = 20 m

From the kinematic equations of projectile motion we have

The time taken to hit the ground is 0.57 s.

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0.57 seconds

Explanation:

If we just want to know how long it takes for the ball to hit the ground, it means only things happening in the vertical direction matter. The the horizontal velocity v and the 20m range of the ball don't matter for this question.

Given:

d = 1.6m

a = 9.8 m/s^2

vi = 0 m/s (this is the initial VERTICAL speed)

t = ?

d = vi * t + 0.5at^2

1.6 = 0 + 0.5(9.8)t^2

1.6 = 4.9t^2

t^2 = 0.33

t = 0.57