What change in entropy occurs when a 0.15 kg ice cube at -18 °c is transformed into steam at 120 °c 4.

The change in entropy of the given process is 1324.8 J/K

Explanation:

The processes involved in the given problem are:

Pressure is taken as constant.

To calculate the entropy change for same phase at different temperature, we use the equation:

     .......(1)

where,

= Entropy change

= specific heat capacity of medium

m = mass of ice = 0.15 kg = 150 g    (Conversion factor: 1 kg = 1000 g)

= final temperature

= initial temperature

To calculate the entropy change for different phase at same temperature, we use the equation:

     .......(2)

where,

= Entropy change

m = mass of ice

= enthalpy of fusion of vaporization

T = temperature of the system

Calculating the entropy change for each process:

We are given:

Putting values in equation 1, we get:

We are given:

Putting values in equation 2, we get:

We are given:

Putting values in equation 1, we get:

We are given:

Putting values in equation 2, we get:

We are given:

Putting values in equation 1, we get:

Total entropy change for the process =

Total entropy change for the process =

Hence, the change in entropy of the given process is 1324.8 J/K

4

explanation:

4

0.19 m/s and 0.45 m/s