Aparticle's position is defined by: x = 4t^3-27t^2+17t+8, where x is expressed in meters and t in seconds. determine (a) the total distance traveled the 2nd time the velocity is zero and (b) the velocity when the acceleration is zero.

a)x = 100.56

b) t = 2.25 s

Explanation:

given equation

x = 4 t³ - 27 t² + 17 t + 8

to get velocity we need to differentiate the expression w.r.t time

on solving the differential equation

v = 12 t² -54 t + 17

at v = 0

using quadratic equation to solve

we get

t = 4.16 s and 0.34 s

x = 4 × 4.16³ - 27 ×  4.16² + 17 × 4.16 + 8

x = -100.56

x = 100.56

b) v = 12 t² -54 t + 17

to get acceleration we need to differentiate the expression w.r.t time

on solving the differential equation

a = 24 t -54

time at which acceleration will be zero

24 t  = 54

t = 2.25 s

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answer: a. same unit

explanation: