Afuse in a motor vehicle electrical system has a resistance of 0.05 ω. it is designed to blow when the power dissipation exceeds 50 w. what is the current rating of the fuse?

31,6 A

Explanation: In order to answer this question we have to use the exptression for the power for any electric sysyem which is given by:

P=I*V  where I and V are the current and voltage.

This system can operate as maximum  at 50 W so by using Ohm law

P= I^2*R  in this case R=0.05Ω

The I= (50 /0.05)^1/2= 31.6 A

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation