What must be the distance (in meters) between a point charge q1 = 16 μc and a point charge q2 = 32 μc for the electrostatic force between them to have a magnitude of 9 newtons?

d = 0.71 meters

Explanation:

It is given that,

Charge 1,

Charge 2,

Electrostatic force between charges, F = 9 N

Let d is the distance between the charges. The electrostatic force between the charges is given by the product of charges and divided by square of distance between them. Mathematically, it is given by :

d = 0.71 meters

So, the distance between the charges is 0.71 meters. Hence, this is the required solution.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west