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Physics, 04.10.2019 20:00 hinojosachristian1

You are using a gas powered pump to raise 100 kg of water to a height of 100 m. the energy efficiency of the pump is 20%. by what amount has the internal energy of the water and pump changed?

for this problem i first did:

change in potential energy = mgh
change in potential energy = 100 * 9.81 * 100
change in potential energy = 98.1 kj

but i don't know how to use the efficiency

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Answers: 3

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