Acar traveling 24.5 m/s runs over a cliff and lands 8 m away from the base. how high is the cliff?

0.522 m

Explanation:

This situation is related to projectile motion, where the initial velocity of the car has only the horizontal component. This means the angle is equal to zero (). And the equations we will use to find the height of the cliff are:

(1)  

Where:  

is the final height of the car

is the initial height

is the initial velocity of the car

is the time

is the acceleration due to gravity

is the angle

is the horizontal distance traveled by the car after passing the cliff

Well, firstly we have to find  from (1):

(3)  

(4)  

Substituting (4) in (2):

(5)  

Isolating :

(6)  

(7)  

Finally:

ι вєℓιєνє ιт ιѕ тнє fιяѕт ¢нσι¢є(α.)

нє ѕнσυℓ∂ ѕмιℓє ρσℓιтℓу αи∂ ѕρєαк тσ тнє ρєяѕσи ωнσ ιѕ ιитєяяυριиg αfтєя тнє ∂ιѕ¢υѕѕισи

нσρє ι ¢συℓ∂ нєℓρ.